You place a cup of 205oF coffee on a table in a room that is 72oF, and 10 minutes later, it is 195oF. Approximately how long will it be before the coffee is 180oF? Use Newton's law of cooling: / [T (t) = T _{A} + (T _{o}-T _{A}) e ^{-kt}/]

A. 15 minutes

B. 25 minutes

C. 1 hour

D. 45 minutes

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6 April, 02:09

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Gabriel Hebert · Answer 1

Temp first number is 205-72=133

second number is 195-72=123

This takes 10 minutes to occur, so you can model this as: 133 (123133) t (10)

You place a cup of 205oF coffee on a table in a room that is 72oF, and 10 minutes later, it is 195oF. Approximately how long will it be before the coffee is 180oF? Use Newton's law of cooling: / [T (t) = T _{A} + (T _{o}-T _{A}) e ^{-kt}/]A. 15 minutesB. 25 minutesC. 1 hourD. 45 minutes