A driver of a car traveling at 15.0m/s applies the brakes, causing a uniform acceleration of - 2.0m/s^2. how long does it take the car to accelerate to a final speed of 10.0m/s? how far has the car moved during the breaking period?

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30 September, 01:32

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Reed Adkins · Answer 1

V=V₀+at

at=V-V₀

t = (V-V₀) / a

t = (10-15) / (-2) = 2.5 s

S=V₀t+at²/2

S=15*2.5-2 * (2.5) ²/2=31.25 meters

2.5 s and 31.25 m