A bicyclist and his bike together have a mass of 70 kg and a speed of 6 m/s. How much work would be done for the biker to accelerate to 10 m/s?

Correct answer: W = 2,240 J

Explanation:

Given:

m = 70 kg

V₁ = 6 m/s

V₂ = 10 m/s

W = ?

Work is a measure of change in this case of kinetic energy:

W = ΔE = (m V₂²) / 2 - (m V₁²) / 2 = (m / 2) · (V₂² - V₁²)

W = (70 / 2) · (10² - 6²) = 35 · (100 - 36) = 35 · 64 = 2,240 J

W = 2,240 J

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