A 600 n volleyball player lands from a spike attempt and immediately jumps up to try for a block. when she first contacts the ground, her velocity is 3 m/s downward, and then as she leaves the ground for the block her velocity is 4 m/s upward. her kinetic energy as she leaves the ground is

Kinetic energy of the player as she leaves the ground=490 J

Explanation:

Weight of the volley ball player = 600 N

weight = mg

m = mass

g = acceleration due to gravity=9.8 m/s²

so 600 = m (9.8)

m=61.2 kg

Now the kinetic energy is given by KE = 1/2 mv²

v = velocity of the player as she leaves the ground = 4 m/s

KE = 1/2 (61.2) (4) ²

KE = 490 J