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8 March, 16:46

A 600 n volleyball player lands from a spike attempt and immediately jumps up to try for a block. when she first contacts the ground, her velocity is 3 m/s downward, and then as she leaves the ground for the block her velocity is 4 m/s upward. her kinetic energy as she leaves the ground is

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  1. 8 March, 16:56
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    Kinetic energy of the player as she leaves the ground=490 J

    Explanation:

    Weight of the volley ball player = 600 N

    weight = mg

    m = mass

    g = acceleration due to gravity=9.8 m/s²

    so 600 = m (9.8)

    m=61.2 kg

    Now the kinetic energy is given by KE = 1/2 mv²

    v = velocity of the player as she leaves the ground = 4 m/s

    KE = 1/2 (61.2) (4) ²

    KE = 490 J
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