A 60.0-kg person is in an elevator with a mass of 2000 kg. The elevator moves vertically up through a distance of 24.0 m with a constant speed of 4.00 m/s. How much work is done on this elevator system? Use g=10.0m/s^2.

Question

Jabari Moore

Physics

8 July, 23:26

A 60.0-kg person is in an elevator with a mass of 2000 kg. The elevator moves vertically up through a distance of 24.0 m with a constant speed of 4.00 m/s. How much work is done on this elevator system? Use g=10.0m/s^2.

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Genesis Burch · Answer 1

The mass of the (elevator + person) is (2,000 kg + 60 kg) = 2,060 kg.

The weight is (mass x gravity) = (2,060 x 10) = 20,600 newtons

Work = (force x distance) = (20,600 newtons x 24m) = 494,400 joules

The speed, acceleration, and how much time it takes don't make any

difference, unless you want the average power during the lift.

Power = (work) / (time) =

494,000 J / (24/4 m) =

494,000 J / 6 sec = 82,400 watts wow!