What is the average kinetic energy in joules of hydrogen atoms on the 5500ºc surface of the sun?

The kinetic energy is related to the temperature of the system using this formula:

E = (3/2) kT

where

k is the Boltzmann's constant (1.38*10⁻²³ J/K)

The temperature in K is:

T = 5500 + 273 = 5773 K

E = (3/2) (1.38*10⁻²³ J/K) (5773 K)

E = 1.195*10⁻¹⁹ J