A baseball is popped straight up into the air and has a hang-time of 6.25 S.

Determine the height to which the ball rises before it reaches its peak. (Hint: the

time to rise to the peak is one-half the total hang-time.)

Question

Liu

Physics

18 September, 16:10

A baseball is popped straight up into the air and has a hang-time of 6.25 S.

Determine the height to which the ball rises before it reaches its peak. (Hint: the

time to rise to the peak is one-half the total hang-time.)

+1

Answers (1)

Know the Answer?

Tommy Nolan · Answer 1

47.9 m

Explanation:

Given:

y₀ = 0 m

t = 6.25/2 = 3.125 s

v = 0 m/s

a = - 9.8 m/s²

Find: y

y = y₀ + vt - ½ at²

y = 0 + (0) (3.125) - ½ (-9.8) (3.125) ²

y = 47.9 m

A baseball is popped straight up into the air and has a hang-time of 6.25 S.Determine the height to which the ball rises before it reaches its peak. (Hint: thetime to rise to the peak is one-half the total hang-time.)

A baseball is popped straight up into the air and has a hang-time of 6.25 S.

Determine the height to which the ball rises before it reaches its peak. (Hint: the

time to rise to the peak is one-half the total hang-time.)