A 2 kg mass hangs motionless from a partially stretched spring having a spring constant of 172 N/m. What is the magnitude of the force (in N) that would be required to pull the mass down by an additional 5 cm? Never include units with your answer.

Question

Jags

Physics

27 February, 02:05

A 2 kg mass hangs motionless from a partially stretched spring having a spring constant of 172 N/m. What is the magnitude of the force (in N) that would be required to pull the mass down by an additional 5 cm? Never include units with your answer.

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Answers (1)

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Dashawn Bowman · Answer 1

8.608 N

Explanation:

m = 2 kg, K = 172 N/m

Let the extension is x.

F = K x

x = mg / K = 2 x 9.8 / 172 = 0.114 m

now d = 5 cm = 0.05 m

Let additional force is F.

(mg + F) = K (x + d)

(2 x 9.8 + F) = 172 (0.114 + 0.05)

19.6 + F = 28.208

F = 8.608 N