Two electric charges are moved so that they are twice as far apart as they had originally been. Is the force they experience from each other now half the original force? Explain.

The force would be a quarter of its original

Explanation:

Since ... Force is directly proportional to the square of separation

; F = k/r^2 ... where k is just a constant ... it won't change.

; So hence ... we will take an example

i. e If the Force = 4 newtons when the charges are separated by 2 metres

; we firstly calculate the constant k

; 4 = k / (2) ^2

; Hence giving us ... k = 16

So if the separation distance is increased by factor of 2 ... Separation (r) = 4 metres ... So to see what happens to the force ...

; F = 16 / (4) ^2

Hence giving us that the Force = 1 newton

So hence if the separation distance is increased by factor of 2 ... then the force would be a 1/4 of its original

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