Jayme, who has a mass of 40 kg, is ice-skating and traveling at 4 m/s to the north towards anthony, who has a mass of 65 kg and is traveling south at 12 m/s towards jayme. as the two approach each other, jayme suddenly grabs the arm of anthony. while holding his arm, the two continue skating together. what is the final velocity of jayme and anthony skating together

Question

Cierra Riddle

Physics

6 April, 05:34

Jayme, who has a mass of 40 kg, is ice-skating and traveling at 4 m/s to the north towards anthony, who has a mass of 65 kg and is traveling south at 12 m/s towards jayme. as the two approach each other, jayme suddenly grabs the arm of anthony. while holding his arm, the two continue skating together. what is the final velocity of jayme and anthony skating together

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Answers (1)

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Emilee Holloway · Answer 1

Jayme = >m1 = 40 kg, v1 = 4 m/s, North

Antony = >m2 = 65 kg, v2 = 12 m/s South

Jayme + Antony = > mf = 105 kg, vf = ?

This is a question of conservation of momentum. Therefore;

m1v1 + m2v2 = mfvf

Substituting;

40*4 + 65*12 = 105*vf

160 + 780 = 105vf

940 = 105vf

vf = 940/105 = 8.95 m/s

The velocity of Jayme and Antony skating together will be 8.95 m/s.