To determine the specific heat of an object, a student heats it to 100 degrees C in boiling water. She then places the 110 g object in a 172 g aluminum calorimeter containing 148 g of water. The aluminum and water are initially at a temperature of 19.6 degrees, and are thermally insulated from their surroundings.

If the final temperature is 23.8 degrees, what is the specific heat of the object?

Cs=912.6J/kg/K

Explanation:

Sum of Heat gained=sum heat lośs

Definition of terms

Ms=mass of substance 0.11kg

Cs=specific heat capacity of the substance?

Ts = temperature of the substance

Tm = temperature of mixture 28.8°C

Tal = temperature of aluminium19.6°C

Tw=temperature of water 19.6°C

Mal=mass of aluminium 0.172kg

Mw=mass of water 0.148kg

Cw = specific heat capa of water 4200j/kgk

Cal=specific heat capacity of aluminium 903j/kgk

Having gotten all the parameters needed

Ms*Cs * (Ts-Tm) = Mw*Cw * (Tm-Tw) + Mal*Cal * (Tm-Tal)

0.11*Cs * (100-28.8) = 0.148*4200 * (28.8-19.6) + 0.172*903 * (28.8-19.6)

cs= = ((4467267) / (4895))

Cs=912.61Jkg-1K-1