A 120kg defensive lineman tackles a stationary quarterback at 6.5 m/s it takes. 25 seconds for the lineman to completely stop what is the magnitude of force exerted on the lineman during the collision

F = - 3120 N

Explanation:

Lets write out everything we have:

Lineman:

m = 120kg

V1 = 6.5m/s

v2 = 0

t = 0.25

We should find acceleration, to move on to the next step;

a = v2-v1 / t

a = 0 - 6.5 / 0.25

a = - 26m/s^2

Now we can use the Fnet formula and solve for F;

Fnet = ma

fnet = (120) (-26)

F = - 3120 N