A particle is launched at an angle of 37° from horizontal. If the horizontal velocity component is 7.65 meters/second, what is the resultant velocity of the particle?

This problem can be solved using trigonometric relations. Since the angle and the horizontal component are given, then this can be solved by treating it as a right triangle. This is shown below:

sin 37 = 7.65 / x

x = 7.65 / sin 37

x = 12.71 m/s