How many grams of ice at 0°c will melt if 1.50 kj of heat are added? (the molar heat of fusion of water is 6.01 kj/mol.) 4.49 g 12.0 g 7.51 g 2.99 g?

The computation would be:moles = mass / Molar Mass, but we are looking for the mass, so rearranging, will give us: mass = moles x MM

Q = moles x Hf

Q = (mass/MM) x Hf

mass = (Q x MM) / Hf

= (1.50-kJ x 18.0-g/mol) / 6.01-kJ/mol

=4.49 g H20 is the answer