Ask Question
14 August, 13:22

Tina is looking out a window and throws marble straight downward toward the sidewalk below at a speed of 5.00 m/s and the window is 39.0 meters above the sidewalk. Answer the two questions below, using three significant digits. Part A: What is the speed of the ball (11) when it hits the ground? Number m/s (Remember: enter a magnitude.) Part B: After 1.90 s, how far down has the marble travelled?

+4
Answers (1)
  1. 14 August, 13:27
    0
    a) 28.1 m/s

    b) 27.2 m

    Explanation:

    a)

    Consider the motion of the marble in downward direction taking down direction as positive

    v₀ = initial velocity = 5 m/s

    v = final velocity as it hits the ground = ?

    a = acceleration = 9.8 m/s²

    d = vertical height traveled = 39 m

    Using the equation

    v² = v₀² + 2 a d

    v² = 5² + 2 (9.8) (39)

    v = 28.1 m/s

    b)

    t = time of travel = 1.90 s

    y = vertical distance traveled

    Using the equation

    y = v₀ t + (0.5) a t²

    y = (5) (1.90) + (0.5) (9.8) (1.90) ²

    y = 27.2 m
Know the Answer?
Not Sure About the Answer?
Find an answer to your question 👍 “Tina is looking out a window and throws marble straight downward toward the sidewalk below at a speed of 5.00 m/s and the window is 39.0 ...” in 📗 Physics if the answers seem to be not correct or there’s no answer. Try a smart search to find answers to similar questions.
Search for Other Answers