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17 August, 16:07

5. A balloon is ascending at the rate of 4.9m/s. A pocket is dropped from the balloon when situated at a height of 245m. How long does it take the packet to reach the ground? What is its final velocity?

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  1. 17 August, 16:26
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    initial velocity, u = 4.9 m/s

    final velocity = v m/s

    initial height, h₁ = 245 m

    final height, h₂ = 0

    a = - 9.8 m/s²

    time taken = t seconds

    s = ut + 0.5at²

    ⇒ (h₂-h₁) = ut + 0.5at²

    ⇒ 0-245 = 4.9t + 0.5 * (-9.8) * t²

    ⇒ - 245 = 4.9t - 4.9t²

    ⇒ 4.9t² - 4.9t - 245 = 0

    Solving it, we get t = 7.59s

    v = u + at = 4.9 - 9.8*7.59 = 4.9 - 74.38 = - 69.48 m/s

    velocity is 69.48 m/s downward
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