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20 June, 02:41

What is the molality of a solution that contains 54 grams of NaOH dissolved in 1.50 kg of water? (The molar mass of NaOH 40.00 grams/moles.)

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  1. 20 June, 03:01
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    0.900 mol/kg

    Explanation:

    Molality is moles of solute per kilograms of solvent.

    Converting 54 grams of NaOH to moles:

    54 g NaOH * (1 mol NaOH / 40.00 g NaOH) = 1.35 mol NaOH

    So the molality is:

    m = (1.35 mol) / (1.50 kg)

    m = 0.900 mol/kg
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