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9 July, 23:53

A rock is dropped from the top of a tower. When it is 40 meters above the ground velocity of 17 m/s. When its velocity is 24 m/s, how far is it above the ground? Select one: O a. 29.4 meters o b. 25.4 meters o c. 33.3 meters d. 10.7 meters O e. 147 meters

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  1. 9 July, 23:55
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    Option B is the correct answer.

    Explanation:

    Let us consider 40 meter above ground as origin.

    Initial velocity = 17 m/s

    Final velocity = 24 m/s

    Acceleration = 9.81 m/s

    We have equation of motion v² = u² + 2as

    Substituting

    24² = 17² + 2 x 9.81 x s

    s = 14.63 m

    Distance traveled by rock = 14.63 m down.

    Height of rock from ground = 40 - 14.63 = 25.37 m = 25.4 m

    Option B is the correct answer.
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