A 0.140 kg baseball is thrown horizontally with a velocity of 28.9 m/s. It is struck with a constant horizontal force that lasts for 1.85 ms, which results in a velocity of 37.0 m/s in the opposite direction. What was the magnitude of the horizontal force?

A) 0.613 kN

B) 2.19 kN

C) 2.80 kN

D) 4.99 kN

Question

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Physics

25 October, 11:19

A 0.140 kg baseball is thrown horizontally with a velocity of 28.9 m/s. It is struck with a constant horizontal force that lasts for 1.85 ms, which results in a velocity of 37.0 m/s in the opposite direction. What was the magnitude of the horizontal force?

A) 0.613 kN

B) 2.19 kN

C) 2.80 kN

D) 4.99 kN

+3

Answers (1)

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Darren · Answer 1

Option D is the correct answer.

Explanation:

Force = Mass x Acceleration

F = ma

m = 0.14 kg

We have equation of motion v = u + at

Initial velocity, u = 28.9 m/s

Final velocity, v = - 37 m/s

Time, t = 1.85 ms = 0.00185 s

Substituting

v = u + at

-37 = 28.9 + a x 0.00185

a = - 35621.62 m/s²

Acceleration, a = - 35621.62 m/s²

F = ma = 0.14 x - 35621.62 = - 4.99 kN

Option D is the correct answer.

A 0.140 kg baseball is thrown horizontally with a velocity of 28.9 m/s. It is struck with a constant horizontal force that lasts for 1.85 ms, which results in a velocity of 37.0 m/s in the opposite direction. What was the magnitude of the horizontal force?A) 0.613 kNB) 2.19 kNC) 2.80 kND) 4.99 kN