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14 November, 14:30

I start going 10 m/sIf I slow down at 2 m/s/s how far will I go before I stop

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  1. 14 November, 14:50
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    25 m

    Explanation:

    Given:

    v₀ = 10 m/s

    v = 0 m/s

    a = - 2 m/s²

    Find: Δx

    v² = v₀² + 2aΔx

    (0 m/s) ² = (10 m/s) ² + 2 (-2 m/s²) Δx

    Δx = 25 m
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