An ideal transformer has LaTeX: N_1 = 1000 N 1 = 1000 (number of windings on the primary side), and LaTeX: N_2 = 8000 N 2 = 8000 (number of windings on the secondary side). If the rms voltage on the primary side is LaTeX: V_{rms}=100V V r m s = 100 V, what is the rms voltage on the secondary side? Give your answer in terms of Volts (rms), without entering the units.

Question

Matthew Padilla

Physics

14 April, 08:14

An ideal transformer has LaTeX: N_1 = 1000 N 1 = 1000 (number of windings on the primary side), and LaTeX: N_2 = 8000 N 2 = 8000 (number of windings on the secondary side). If the rms voltage on the primary side is LaTeX: V_{rms}=100V V r m s = 100 V, what is the rms voltage on the secondary side? Give your answer in terms of Volts (rms), without entering the units.

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Answers (1)

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Alexandra Mccann · Answer 1

V₂ = 800 Volts (rms)

Explanation:

The turns ratio of an ideal transformer is given by the following formula:

N₁/N₂ = V₁/V₂

where,

N₁ = No. of turns in primary coil of the transformer = 1000 N

N₂ = No. of turns in secondary coil of the transformer = 8000 N

V₁ = rms Voltage on primary side of the transformer = 100 V

V₂ = rms Voltage on secondary side of the transformer = ?

Therefore, using these values in equation, we get:

1000 N/8000 N = 100 V/V₂

V₂ = (100) (8) Volts

V₂ = 800 Volts (rms)