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30 May, 08:09

A car makes a trip due north for three-fourths of the time and due south one-fourth of the time. The average northward velocity has a magnitude of 31 m/s, and the average southward velocity has a magnitude of 43 m/s. Taking northward to be the positive direction, what is the average velocity for the trip?

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  1. 30 May, 08:18
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    The average speed is 34 m/s

    Explanation:

    The average speed a body is defined for the total distance traveled between the total time

    Let's calculate the distance the car travels.

    X = V t

    Northward

    X1 = 31 ¾ t

    To the south

    X2 = 43 ¼ t

    The total distance and time are, we can add the distance as scalars by the movement being on the same North-South line

    Xt = X1 + X2

    t all = ¾ t + ¼ t = t

    Xt = 31 ¾ t + 43 ¼ t

    Xt = t (23.25 + 10.75)

    Xt = t (34)

    We calculate the average speed

    V = t 34 / t

    V = 34 m / s

    The average speed is 34 m / s
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