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15 August, 05:30

A truck traveling at 80 mph runs into a bridge abutment and crumples for 0.8 m before coming to a full stop. If we estimate the process as constant deceleration motion, what is the average force exerted on the car, with mass 3500 kg, during the collision process

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  1. 15 August, 05:32
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    U = 80mph = 35.76m/s

    S = 0.8m

    M = 3500kg

    To find the deceleration, we use equation of motion to calculate that

    V² = u² + 2as

    But v = 0

    0 = u² + 2as

    -U² = 2as

    a = - u² / 2s

    a = - (35.76) ² / (2 * 0.8)

    a = 1278.78 / 1.6 = 799.24 m/s²

    The force exerted on the truck during deceleration is equal to the summation of all the forces acting on the truck.

    ∑F = m. ⃗a

    -F = 3500 * 799.24

    F = - 2797331.25N

    F = - 2797.33kN

    F = - 2.797MN.
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