Ask Question
4 August, 00:29

Determine the magnitude and direction of the force between two parallel wires 35 m long and 3.0 cm apart, each carrying 35 a in the same direction.

+4
Answers (1)
  1. 4 August, 00:32
    0
    Answer;

    = 0.2858 N, attractive

    Explanation;

    Since the currents are parallel, the force on each wire will be attractive, toward the other wire. Therefore; to calculate the magnitude of force we use the formula;

    F2 = (μ₀/2π) (I₁I₂/d) I₂

    Where;

    μ₀ = constant = 4π * 10^-7 H/m,

    I₁, I₂ are the currents,

    L s the length o the wire,

    d is the distance between these two wires

    if current are in same direction, they exert attractive force on each other and if currents are in opposite direction, they exert repulsive force

    Therefore;

    F₂ = (4π * 10^-7 T. m/A) / 2π) * ((35 A) ² / 0.03 m) * 35 m

    = 0.2858 N, attractive
Know the Answer?
Not Sure About the Answer?
Find an answer to your question 👍 “Determine the magnitude and direction of the force between two parallel wires 35 m long and 3.0 cm apart, each carrying 35 a in the same ...” in 📗 Physics if the answers seem to be not correct or there’s no answer. Try a smart search to find answers to similar questions.
Search for Other Answers