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24 February, 06:24

If a body travels half its total path in the last 1.50 s of its fall from rest, find the total time of its fall (in seconds).

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  1. 24 February, 06:31
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    time to fall is 3.914 seconds

    Explanation:

    given data

    half distance time = 1.50 s

    to find out

    find the total time of its fall

    solution

    we consider here s is total distance

    so equation of motion for distance

    s = ut + 0.5 * at² ... 1

    here s is distance and u is initial speed that is 0 and a is acceleration due to gravity = 9.8 and t is time

    so for last 1.5 sec distance is 0.5 of its distance so equation will be

    0.5 s = 0 + 0.5 * (9.8) * (t - 1.5) ² ... 1

    and

    velocity will be

    v = u + at

    so velocity v = 0 + 9.8 (t-1.5) ... 2

    so first we find time

    0.5 * (9.8) * (t - 1.5) ² = 9.8 (t-1.5) + 0.5 (9.8)

    solve and we get t

    t = 3.37 s

    so time to fall is 3.914 seconds
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