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13 July, 02:51

On a very muddy football field, a 110kg linebacker tackles an 85kg halfback. Immediately before the collision, the linebacker is slipping with a velocity of 8.8m/s north and the halfback is sliding with a velocity of 7.2m/s east.

A. What is the magnitude of the velocity at which the two players move together immediately after the collision?

B. What is the direction of this velocity?

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  1. 13 July, 03:20
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    A. the magnitude of the velocity at which the two players move together immediately after the collision is 7.9m/s

    B. The direction of this velocity is due north as the linebacker since he has obviously has more momentum

    Explanation:

    This problem bothers on the inelastic collision

    Given data

    Mass of linebacker m1 = 110kg

    Mass of halfbacker m2 = 85kg

    Velocity of linebacker v1 = 8.8m/s

    Velocity of halfbacker v2 = 7.2m/s

    Applying the principle of conservation of momentum for inelastic collision we have

    m1v1 + m2v2 = (m1+m2) v

    Where v is the common velocity after impact

    Substituting our data into the expression we have

    110*8.5+85*7.2 = (110+85) v

    935+612=195v

    1547=195v

    v=1547/195

    v=7.9m/s

    Momentum of linebacker after impact = 110*7.9 = 869Ns

    Momentum of halfbacker after impact = 85*7.9 = 671.5Ns

    the direction after impact is due north since the linebacker has greater momentum
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