A rugby player passes the ball 7.00 m across the field,

where it is caught at the same height as it left his hand. At

what angle was the ball thrown if its initial speed was 12.0 m/s? (in degrees)

Question

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Physics

23 April, 01:37

A rugby player passes the ball 7.00 m across the field,

where it is caught at the same height as it left his hand. At

what angle was the ball thrown if its initial speed was 12.0 m/s? (in degrees)

+5

Answers (1)

Know the Answer?

Darien Anthony · Answer 1

The horizontal distance between the origin and the final destination of a projectile is referred to as the range of the projectile. This can be calculated through the equation,

R = v₀²sin2θ / g

where R is the range, v₀ is the initial velocity, θ is the angle and g is the acceleration due to gravity.

Substituting the known values from the given above,

7 = (12 m/s) ² (sin2θ) / 9.8 m/s²

The value of θ from the equation is 14.22°.

A rugby player passes the ball 7.00 m across the field,where it is caught at the same height as it left his hand. Atwhat angle was the ball thrown if its initial speed was 12.0 m/s? (in degrees)

A rugby player passes the ball 7.00 m across the field,

where it is caught at the same height as it left his hand. At

what angle was the ball thrown if its initial speed was 12.0 m/s? (in degrees)