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13 March, 03:16

A total of 54.0 calories of heat are absorbed as 58.3 g of lead is heated from 12.0° C to 42.0° C. What is the specific heat of lead? A) 0.029 cal gram °C B) 0.022 cal gram °C C) 0.017 cal gram °C D) 0.031 cal gram °C

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  1. 13 March, 03:30
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    The answer is choice D) 0.031 cal gram degrees celsuis
  2. 13 March, 03:35
    0
    Answer: D) 0.031 cal / gram °C

    Explanation:

    Specific Heat can be defined as the amount of heat required to raise the temperature of 1 unit of mass by 1 degree.

    Q = m c ΔT

    where m is the mass, c is the specific heat and ΔT is the difference in temperatures. Q = 54.0 cal

    m = 58.3 g

    ΔT = 42° C - 12°C = 30°C

    c = Q / (mΔT)

    c = 54.0 cal / (58.3 g*30°C) = 0.031 cal / gram °C
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