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23 February, 03:23

If a certain shade of blue has a frequency of 7.33 x 10^14Hz, what is the energy of exactly one photon of this light?

Is this as simple as multiplying the frequency by Planck's constant?

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  1. 23 February, 03:24
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    The best way to express this is by means if this formula: E = h v. H is the plancks constant and v is the frequency. The procedure will look like this:

    E = 6.626 x 10-34 J s (7.33 x 10^14 / s) = 4.857 x 10^-19 J

    That is how we may express the energy. And as you can see, you can solve it with the plancks constant and multiplying the frequency
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