A block slides on a frictionless, horizontal surface with a speed of 1.32 m/s. The block encounters an unstretched spring and compresses it. If it takes the block 0.4 s to come to rest, what would be hte period of oscillation if the block stays stuck to the spring? If the spring extends back the other direction, the block eventually loses contatct with the psring and slides away, what is the velocity of the block when it loses contact with the spring?

Question

Jackie

Physics

13 May, 02:00

A block slides on a frictionless, horizontal surface with a speed of 1.32 m/s. The block encounters an unstretched spring and compresses it. If it takes the block 0.4 s to come to rest, what would be hte period of oscillation if the block stays stuck to the spring? If the spring extends back the other direction, the block eventually loses contatct with the psring and slides away, what is the velocity of the block when it loses contact with the spring?

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Answers (1)

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Burnett · Answer 1

The given time is 1 / 4 of the time period

So Time period of oscillation.

= 4 x. 4 = 1.6 s

When the block reaches back its original position when it came in contact with the spring for the first time, the block and the spring will have maximum

velocity. After that spring starts unstretching, reducing its speed, so block loses contact as its velocity is not reduced.

So required velocity is the maximum velocity of the block while remaining in contact with the spring.

v (max) = w A = 1.32 m / s.