Ask Question
9 January, 01:28

In an experiment, 108 J of work was done on a closed system. During this phase of the experiment, 79 J of heat energy was added to the system. What was the total change in the internal energy of the system?

+1
Answers (1)
  1. 9 January, 01:54
    0
    187 J

    Explanation:

    First Law of Thermodynamics:

    ΔQ = ΔW + ΔU

    ΔQ : Heat. If it added to system then positive and if it is rejected by system then negative.

    ΔW : Work. If it done by the system then positive and if it is done on system then negative.

    ΔU : Internal Energy. If it positive then temperature of system increased and if it is negative then temperature of system decreased.

    ΔQ = 79 J

    ΔW = - 108 J

    ΔU = ?

    substituting the value in the equation:

    79 = - 108 + ΔU

    ∴ ΔU = 187 J
Know the Answer?
Not Sure About the Answer?
Find an answer to your question 👍 “In an experiment, 108 J of work was done on a closed system. During this phase of the experiment, 79 J of heat energy was added to the ...” in 📗 Physics if the answers seem to be not correct or there’s no answer. Try a smart search to find answers to similar questions.
Search for Other Answers