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5 December, 18:58

A 0.500 kg rock is whirled in a vertical circle of a radius 0.60 m. the velocity of the rock at the bottom of the swing is 4.0 m/s. what is the acceleration

A 3.3 m/s^2

B 26.6 m/s^2

C 13.3 m/s^2

D 6.6 m/s^2

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Answers (1)
  1. 5 December, 19:16
    0
    Centripetal acceleration is:

    a = v² / r

    a = (4.0 m/s) ² / 0.60 m

    a = 26.6 m/s²
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