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Hamilton
Physics
12 March, 23:18
D=vt + (1/2) at^2 solve for v
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Drew Flynn
12 March, 23:25
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First multiply each side by 2
then subtract at² from each side
Divide each side by 2t:
v = D/t - at/2
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Sanaa Reeves
12 March, 23:41
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You said D = vt + (1/2) at²
Multiply each side by 2 : 2D = 2vt + at²
Subtract at² from each side : 2D - at² = 2vt
Divide each side by 2t : v = (2D - at²) / 2t
v = D/t - at/2
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