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17 January, 18:31

A piece of aluminum has a volume of 4.89 x 10-3 m3. The coefficient of volume expansion for aluminum is = 69 x 10-6 (C°) - 1. The temperature of this object is raised from 19.1 to 357 oC. How much work is done by the expanding aluminum if the air pressure is 1.01 x 105 Pa?

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  1. 17 January, 18:46
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    11.515 Joule

    Explanation:

    Volume of aluminium = V = 4.89*10⁻³ m³

    Coefficient of volume expansion for aluminum = α = 69*10⁻⁶ / °C

    Initial temperature = 19.1°C

    Final temperature = 357°C

    Pressure of air = 1.01*10⁵ Pa

    Change in temperature = ΔT = 357-19.1 = 337.9 °C

    Change in volume

    ΔV = αVΔT

    ⇒ΔV = 69*10⁻⁶*4.89*10⁻³*337.9

    ⇒ΔV = 114010.839*10⁻⁹ m³

    Work done

    W = PΔV

    ⇒W = 1.01*10⁵*114010.839*10⁻⁹

    ⇒W = 11.515 J

    ∴ Work is done by the expanding aluminum is 11.515 Joule
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