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31 January, 09:40

honor physics The velocity of a 200 kg object is changed from 5 m/s to 25 m/s in 50 seconds by an applied constant force. a. What change in momentum does the force produced? by. What is the magnitude of the force?

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  1. 31 January, 10:54
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    (a) 4000 kgm/s.

    (b) 80 N

    Explanation:

    (a) Change in momentum: This can be defined as the product of the mass of a body and its change in velocity. The S. I unit of impulse is Ns or kgm/s

    Mathematically, Change in momentum is expressed as

    ΔM = mΔv ... Equation 1

    Where ΔM = change in momentum, m = mass of the object, Δv = change in velocity = v₂ - v₁

    Given: m = 200 kg, Δv = v₂ - v₁ = 25-5 = 20 m/s.

    Substituting into equation 1

    ΔM = 200 (20)

    ΔM = 4000 kgm/s.

    Hence the change in momentum = 4000 kgm/s

    (b)

    Force: This can be defined as the ratio of the change in momentum of a body to the time required for the change.

    F = ΔM/t ... Equation 2

    Where F = force, ΔM = change in momentum, t = time.

    Given: ΔM = 4000 kgm/s, t = 50 second.

    Substituting into equation 2

    F = 4000/50

    F = 80 N.

    Hence the force = 80 N
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