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12 February, 12:37

A 2.4-kg cart is rolling along a frictionless, horizontal track towards a 1.7-kg cart that is held initially at rest. The carts are loaded with strong magnets that cause them to attract one another. Thus, the speed of each cart increases. At a certain instant before the carts collide, the first cart's velocity is 4.1 m/s, and the second cart's velocity is - 2.8 m/s. (a) What is the total momentum of the system of the two carts at this instant

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  1. 12 February, 12:38
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    Mass of first cart M1=2.4kg

    Velocity of first cart U1=4.1m/s

    Mass of second cart M2=1.7kg

    Second cart is initially at rest U2=0

    After an instant, the velocity of the second cart is U2=-2.8m/s

    Now after collision the two cart move together with the same velocity I. e inelastic collision

    Using conservation of momentum

    Momentum before collision, = momentum after collision

    M1U1 + M2U2 = (M1+M2) V

    2.4*4.1 + 1.7 * - 2.8 = (2.4+1.7) V

    9.84 - 4.76 = 4.1V

    5.08=4.1V

    V=5.08/4.1

    V=1.24m/s

    The momentum of the two cart at that instant is

    M1U1+M2U2

    2.4*4.1 + 1.7 * - 2.8

    9.84 - 4.76

    5.08kgm/s

    So the momentum at the instant the velocity is 4.1m/s for cart 1 and - 2.8m/s for cart 2 is 5.08kgm/s
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