Ask Question
5 May, 12:13

While standing on a bridge 40.0 m above the ground, you drop a stone from rest. when the stone has fallen 3.80 m, you throw a second stone straight down. what initial velocity must you give the second stone if they are both to reach the ground at the same instant? take the downward direction to be the negative direction?

+4
Answers (1)
  1. 5 May, 12:20
    0
    Given: distance 1 d₁ = 40 m; distance 2 d₂ = 3.8 m g = - 9.8 m/s²

    Initial Velocity Vi = 0 Final Velocity of stone 2 is unknown = ?

    Total distance dₓ = d₁ - d₂ = 40 m - 3.8 m = 36.2 m

    Formula: a = Vf² - Vi²/2d derive for Final Velocity Vf

    acceleration is now due to gravity, therefore a = g

    Vf = √2gd Vf = √2 (9.8 m/s²) (36.2 m)

    Vf = 26.64 m/s

    Reason: The second stone will still start from rest.
Know the Answer?
Not Sure About the Answer?
Find an answer to your question 👍 “While standing on a bridge 40.0 m above the ground, you drop a stone from rest. when the stone has fallen 3.80 m, you throw a second stone ...” in 📗 Physics if the answers seem to be not correct or there’s no answer. Try a smart search to find answers to similar questions.
Search for Other Answers