A student travels from st. louis to indianapolis, a distance of 210 mi, in 7.0 h. the return trip over the same route takes 6.0 h. what is the average speed for

The average speed for the student is equal to the total distance traveled divided by the total time it took to travel that distance.

(210mi+210mi) / (7h+6h) Simplify and you have your answer!

The average speed is equal to the total distance divided by the time

In the first travel, we have S1 = 210mi/7.0h = 30mi/h

In the second travel the time changes, and we have: S2 = 210mi/6h = 35mi/h

Now, the average speed in the total travel (going and returning) is:

St = (210mi + 210mi) / (7h + 6h) = 31.54mi/h