uniform electric field exists between two parallel plates separated by 2.0 cm. The intensity of the field is 15 kN/C. What is the potential difference between the plates?

potential difference V = 300 volts

Explanation:

Given:

d = 2.0 cm = 0.02m

E = 15 kN/C = 15 * 10³ N/C

For a uniform field between two plates, the Electric Filed Intensity (E) is proportional to the potential difference (V) and inversely proportional to distance between the plates.

E = V/d

⇒ V = E*d = 15 * 10³ N/C * 0.02 m = 300 volts (∴1 Nm/C = 1 J/C = 1 volts)