An air track glider of mass m1 = 0.200kg moving at 0.750m/s to the right collides with a glider of mass m2 = 0.400kg at rest. If m1 rebounds and moves to the left with a speed of 0.250m/s, what is the speed and direction of m2 after the collision. Direction is indicated by the sign of the velocity.

Question

Litzy

Physics

31 May, 08:51

An air track glider of mass m1 = 0.200kg moving at 0.750m/s to the right collides with a glider of mass m2 = 0.400kg at rest. If m1 rebounds and moves to the left with a speed of 0.250m/s, what is the speed and direction of m2 after the collision. Direction is indicated by the sign of the velocity.

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London Chandler · Answer 1

lets assume the right direction as positive direction of motion and left direction as negative direction of motion

m₁ = 0.200 kg

v₁ = velocity of m₁ before collision = 0.750 m/s

v'₁ = velocity of m₁ after collision = - 0.250 m/s

m₂ = 0.200 kg

v₂ = velocity of m₂ before collision = 0 m/s

v'₂ = velocity of m₂ after collision=?

using conservation of momentum

m₁ v₁ + m₂ v₂ = m₁ v'₁ + m₂ v'₂

(0.200) (0.750) + (0.400) (0) = (0.200) ( - 0.250) + (0.400) v'₂

v'₂ = 0.500 m/s

so the glider of mass m₂ moves right at speed of 0.500 m/s