A block slides down a slope inclined at 37 degrees. If the slope is frictionless and the block starts off at rest, how fast is it moving after it has traveled 1 meter along the plane? Apply energy-conservation principles to solve.

Vf = 3.435 m/s

Explanation:

Given:

Initial velocity Vi = 0 m/s (starting from Rest position)

θ = 37⁰

Distance S = 1 m

To find: Final Velocity Vf=?

fist we have to find the down slope net acceleration a = g sin θ

a = 9.81 sin 37⁰ = 5.9 m/s²

By 3rd equation of motion

2 a S = Vf² - Vi²

Vf = Square root (2 * 5.9 m/s² * 1 + 0 m/s)

Vf = Square root (11.8)

Vf = 3.435 m/s