What current flows through a 2.62 cm diameter rod of pure silicon that is 23.5 cm long, when 1000 v is applied to it? (such a rod may be used to make nuclear particle detectors, for example.) the resistivity of pure silicon is 2.30 103 ω · m?

Question

Eaton

Physics

10 October, 18:44

What current flows through a 2.62 cm diameter rod of pure silicon that is 23.5 cm long, when 1000 v is applied to it? (such a rod may be used to make nuclear particle detectors, for example.) the resistivity of pure silicon is 2.30 103 ω · m?

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Answers (1)

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Pearl · Answer 1

Resistivity = resistance * Area / Length

resistance = ?

rho = 2.30 * 10^3 ohms meters.

l = 23.5 cm = 0.235 meters.

diameter = 2.62 cm = 0.0262 m

Radius = diameter / 2 = 0.0131 m

Area = pi r^2 where pi = 3.14

Area = 3.14 * 0.0131^2 = 0.000539 m^2

2.30 * 10^3 = R * 0.000539 / 0.235

2.30 * 10^3 * 0.235/0.000539 = R

R = 1002783 which is about 1 meg ohm, but I'll use the calculation here.

E = 1000 V

R = 1 002 783 ohms

I = ?

E = I * R

1000 = I * 1002783 We should really round that resistor to 1 megohm or 1 * 10^6 ohms.

I = 1*10^3 / 1 * 10^6

I = 1 * 10^-3 amp = 1 milliamp. Pretty reasonable all things considered.