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3 November, 00:33

A thief is trying to escape from a parking garage after completing a robbery, and the thief's car is speeding (v = 13 m/s) toward the door of the parking garage (fig. p2.60). when the thief is l = 22 m from the door a police officer flips a switch to close the garage door. the door starts at a height of 9 m and moves downward at 0.6 m/s. if the thief's car is 1.4 m tall, will the thief escape?

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  1. 3 November, 00:39
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    Answer

    Yes, the car reaches the door before the gate closes.

    Explanation

    The time taken by the car to reach at the door.

    Time = distance / time

    = 22/13

    = 1.6923 seconds

    Time taken by the door to close up to the height of the car.

    Distance the door has to move to prevent the car from escaping = 9.1.4 = 7.6 m

    From newton's 2nd law of motion;

    s = ut + 1/2 gt²

    7.6 = 0.6t + 1/2 * 10t²

    7.6 = 0.6t + 5t²

    50t² + 6t - 76 = 0

    Solving this quadrilatic equation,

    t = 28.537 seconds

    Answer: Yes, the car reaches the door before the gate closes.
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