Wooden ball lies in a vessel with water so that half of it is immersed in water.

With what force does the ball press on the bottom of the vessel if the mass of the ball is = 2 kg, the density of the tree is _д = 800 kg / m3, and the density of the water is _в = 1000 kg / m3?

Question

Joselyn Patel

Physics

30 May, 01:28

Wooden ball lies in a vessel with water so that half of it is immersed in water.

With what force does the ball press on the bottom of the vessel if the mass of the ball is = 2 kg, the density of the tree is _д = 800 kg / m3, and the density of the water is _в = 1000 kg / m3?

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Answers (1)

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Tyrese · Answer 1

Downward force acting on the ball is 19.6N

Net force acting on the ball is 1960V N

Explanation:

Given:

Mass of the ball, m = 2kg

Density of ball, σ = 800 kg/m³

Density of water, ρ = 1000 kg/m³

Downward force acting by the ball in the vessel = mg

where, g = 9.8m/s²

F = 2 X 9.8

F = 19.6N

Net force acting on the ball:

Fnet = (ρ - σ) Vg

where,

V is the volume of water

Fnet = (1000 - 800) V X 9.8

Fnet = 1960V N

If the volume is known, then substitute the value of V to find the net force.

Thus, Downward force acting on the ball is 19.6N

Net force acting on the ball is 1960V N

Wooden ball lies in a vessel with water so that half of it is immersed in water.With what force does the ball press on the bottom of the vessel if the mass of the ball is = 2 kg, the density of the tree is _д = 800 kg / m3, and the density of the water is _в = 1000 kg / m3?

Wooden ball lies in a vessel with water so that half of it is immersed in water.

With what force does the ball press on the bottom of the vessel if the mass of the ball is = 2 kg, the density of the tree is _д = 800 kg / m3, and the density of the water is _в = 1000 kg / m3?