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13 February, 06:22

A snowball is launched horizontally from the top of a building at v = 19.6 m/s. If it lands d = 64 meters from the bottom, how high (in m) was the building?

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  1. 13 February, 06:46
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    Answer: height of building = 18.8m

    Explanation: The question is a projectile motion, a two dimensional motion with a vertical constant acceleration (g = - 9.8m/s²) and a constant horizontal velocity (thus making horizontal component of acceleration zero).

    From the question, distance between bottom of building and where the object lands = 64m, initial velocity for throwing the object = 19.6m/s

    The horizontal range formulae is given as

    d = vt

    Where d = horizontal range = 64m, v = initial velocity of throw.

    64 = 19.6 * t

    t = 64 / 19.6

    t = 3.265 s.

    Height (h) of the building is gotten by using the formulae

    h = vt - 1/2gt²

    h = (19.6*3.265) - 1/2*9.8 * (3.265) ²

    h = 71.05 - (104.47/2)

    h = 71.05 - 52.235

    h = 18.8m
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