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20 November, 10:02

For a certain optical medium the speed of light varies from a low value of 1.80 * 10 8 m/s for violet light to a high value of 1.92 * 10 8 m/s for red light. Calculate the range of the index of refraction n of the material for visible light.

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  1. 20 November, 10:11
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    1.56 - 1.67

    Explanation:

    Refractive index of any material is given as the ratio of the speed of light in a vacuum to the speed of light in that medium.

    Mathematically, it is given as:

    n = c/v

    Where c is the speed of light in a vacuum and v is the speed of light in the medium.

    Given that the speed of light in the optical medium varies from 1.8 * 10^8 m/s to 1.92 * 10^8 m/s, we can find the range of the refractive index.

    When the speed is 1.8 * 10^8 m/s, the refractive index is:

    n = (3 * 10^8) / (1.8 * 10^8)

    n = 1.67

    When the speed is 1.92 * 10^8 m/s, the refractive index is:

    n = (3 * 10^8) / (1.92 * 10^8)

    n = 1.56

    Therefore, the range of values of the refractive index of the optical medium is 1.56 - 1.67.
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