Wood has 4 times the heat capacity as steel. If I add the same amount of heat to the same amount of steel and wood, I find the temperature of the steel increases to 40°C. What is the temperature of the wood?

We balance the enthalpy absorbed by the steel and the enthalpy lost by wood. In this case, we use mCp ΔT to describe the problem. Cp (W) is 4 Cp (S). assuming the same mass,

mCp (W) ΔT1 = mCp (S) ΔT2

4 * ΔT1 = 40

ΔT1 = 10. Hence the temperature of the wood is decreased by 10 degrees