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28 April, 16:17

Which of the following statements about the discharging of a capacitor through a lightbulb are correct?

a) Electrons in the wires flow away from the negative plate, toward the positive plate, reducing the charge on the plates.

b) The electric field at a location inside the wire is due to charge on the surface of the wires and charge on the plates of the capacitor.

c) Electrons flow across the gap between the plates of the capacitor, thus reducing the charge on the capacitor.

d) The fringe field of the capacitor decreases as the charge on the capacitor plates decreases.

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  1. 28 April, 16:37
    0
    a) Electrons in the wires flow away from the negative plate, toward the positive plate, reducing the charge on the plates.

    Explanation:

    a) true. The electrons leave the plate and stop by the bulb where the energy dissipates

    b) False the electric field in the entire metal cable is the same because it is an equipotential surface

    c) False electrons cannot jump from the metal plate

    d) False the load does not create a marginal field
  2. 28 April, 16:41
    0
    The answer is: a) Electrons in the wires flow away from the negative plate, toward the positive plate, reducing the charge on the plates.

    Explanation:

    When we have two conductive surfaces in total influence it is said that we have a capacitor and both surfaces are known as the plates or armatures of the condenser.

    One of the surfaces will have a positive charge and the other negative. Since the number of field lines that leave one will stop at the other, the two charges are equal and opposite.

    This means that a capacitor does not store net charge, since it is always zero. When it is said that a capacitor stores this or that charge or is charged, it always refers to the positive plate charge.

    What a capacitor does store is electric energy, because of the electric field between the plates.

    If we connect the charged capacitor to a lamp, it will discharge through the bulb until the capacitor charge is exhausted. The current disappears and the lamp goes out.

    The answer is: a) Electrons in the wires flow away from the negative plate, toward the positive plate, reducing the charge on the plates.
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