The position of an object moving along the x

axis is given by x (t) = 2t^2+t^3 + 1, where x is

in meters and t in seconds. The acceleration of

the object at t = 2 seconds is:

4m/s?

Question

Dear

Physics

9 September, 00:17

The position of an object moving along the x

axis is given by x (t) = 2t^2+t^3 + 1, where x is

in meters and t in seconds. The acceleration of

the object at t = 2 seconds is:

4m/s?

+4

Answers (1)

Know the Answer?

Alena Calhoun · Answer 1

Answer: 16 meters per second

Explanation:

The derivative of the position is the velocity.

The derivative of the velocity is the acceleration.

x (t) = 2t² + t³ + 1

x' (t) = v (t) = 4t + 3t²

x'' (t) = v' (t) = a (t) = 4 + 6t

a (2) = 4 + 6 (2)

= 4 + 12

= 16

The position of an object moving along the xaxis is given by x (t) = 2t^2+t^3 + 1, where x isin meters and t in seconds. The acceleration ofthe object at t = 2 seconds is:4m/s?

The position of an object moving along the x

axis is given by x (t) = 2t^2+t^3 + 1, where x is

in meters and t in seconds. The acceleration of

the object at t = 2 seconds is:

4m/s?