Ask Question
16 April, 07:46

When the pumpkin is shot straight upward with an initial speed of 14 m/s, what is the maximum height above its initial equation

+3
Answers (1)
  1. 16 April, 08:01
    0
    10 m

    Explanation:

    At the maximum height, the velocity is 0.

    Given:

    v₀ = 14 m/s

    v = 0 m/s

    a = - 9.8 m/s²

    Find: Δy

    v² = v₀² + 2aΔy

    (0 m/s) ² = (14 m/s) ² + 2 (-9.8 m/s²) Δy

    Δy = 10 m
Know the Answer?
Not Sure About the Answer?
Find an answer to your question 👍 “When the pumpkin is shot straight upward with an initial speed of 14 m/s, what is the maximum height above its initial equation ...” in 📗 Physics if the answers seem to be not correct or there’s no answer. Try a smart search to find answers to similar questions.
Search for Other Answers